hdu 3549 Flow Problem 网络流
创始人
2024-02-09 06:24:08

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3549

Network flow is a well-known difficult problem for ACMers. Given a graph, your task is to find out the maximum flow for the weighted directed graph.

Input

The first line of input contains an integer T, denoting the number of test cases.
For each test case, the first line contains two integers N and M, denoting the number of vertexes and edges in the graph. (2 <= N <= 15, 0 <= M <= 1000)
Next M lines, each line contains three integers X, Y and C, there is an edge from X to Y and the capacity of it is C. (1 <= X, Y <= N, 1 <= C <= 1000)

Output

For each test cases, you should output the maximum flow from source 1 to sink N.

题意:不能再简单了这题意,很裸的告诉你根据输入来求解最大流。

解法:网络流算法求解最大流,模板题,Dinic。

 1 #include2 #include3 #include4 #include5 #include6 #include7 #include8 #define inf 0x7fffffff9 using namespace std;
10 const int maxn=16;
11 
12 int n,m;
13 int graph[maxn][maxn],d[maxn];
14 
15 int bfs()
16 {
17     memset(d,0,sizeof(d));
18     d[1]=1;
19     queue Q;
20     Q.push(1);
21     while (!Q.empty())
22     {
23         int u=Q.front() ;Q.pop() ;
24         for (int v=1 ;v<=n ;v++)
25         {
26             if (!d[v] && graph[u][v]>0)
27             {
28                 d[v]=d[u]+1;
29                 Q.push(v);
30                 if (v==n) return 1;
31             }
32         }
33     }
34     return 0;
35 }
36 
37 int dfs(int u,int flow)
38 {
39     if (u==n || flow==0) return flow;
40     int cap=flow;
41     for (int v=1 ;v<=n ;v++)
42     {
43         if (d[v]==d[u]+1 && graph[u][v]>0)
44         {
45             int x=dfs(v,min(cap,graph[u][v]));
46             cap -= x;
47             graph[u][v] -= x;
48             graph[v][u] += x;
49             if (cap==0) return flow;
50         }
51     }
52     return flow-cap;
53 }
54 
55 int Dinic()
56 {
57     int sum=0;
58     while (bfs()) sum += dfs(1,inf);
59     return sum;
60 }
61 
62 int main()
63 {
64     int t,ncase=1;
65     scanf("%d",&t);
66     while (t--)
67     {
68         scanf("%d%d",&n,&m);
69         int a,b,c;
70         memset(graph,0,sizeof(graph));
71         for (int i=0 ;i 

相关内容

热门资讯

三联锻造跌0.28%,成交额3... 6月9日,三联锻造跌0.28%,成交额3152.67万元,换手率1.18%,总市值38.88亿元。异...
西测测试涨2.08%,成交额3... 6月9日,西测测试涨2.08%,成交额3.82亿元,换手率5.16%,总市值108.94亿元。异动分...
无锡振华跌0.71%,成交额1... 6月9日,无锡振华跌0.71%,成交额1.74亿元,换手率1.78%,总市值98.03亿元。异动分析...
腾景科技跌1.24%,成交额3... 6月9日,腾景科技跌1.24%,成交额31.28亿元,换手率8.16%,总市值384.51亿元。异动...
圣晖集成涨停,成交额2.18亿... 6月9日,圣晖集成涨停,成交额2.18亿元,换手率2.08%,总市值106.54亿元。异动分析中芯国...